Adobe Interview Question for Software Engineers


Country: United States
Interview Type: Phone Interview




Comment hidden because of low score. Click to expand.
2
of 2 vote

// ZoomBA
def ways_to_dist( target_value ){
   count = 0
   q = list() // create a queue
   q.enqueue ( [0,0,list(0)] ) // add to it
   // now the loop
   while ( !empty(q) ){
     #( prev_inc , cur_sum , path ) = q.dequeue()
     continue ( cur_sum > target_value ) // obvious, nothing else can do
     continue ( cur_sum == target_value  ) {
       println( path ) // for debug diagnostic
       count +=1 // increment possible scenarios
     }
     for ( inc : [1,5,10,25 ] ){
        if ( inc >= prev_inc ){ // ensure sorted path
           q.enqueue( [ inc , cur_sum + inc , path + inc  ] )
        }
     }
   }
   return count
}
println ( ways_to_dist( 42 ))

- NoOne October 10, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

if ( inc >= prev_inc ){ // ensure sorted path

As you can see we only add to the queue when we have seen that current increment should be larger than the previous increment. This way the resulting path remains sorted.

- NoOne October 12, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

How does this work ?

- koustav.adorable October 12, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

How do you ensure that the same combination i.e (1+5+10 and 10+1+5) is not present in queue ?

- koustav.adorable October 12, 2016 | Flag Reply


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