Vezita
BAN USER
- 5
1of 1 vote
AnswersWhat is the output of:
- Vezita in United Statesmain () { printf("%x", -1<<4); }| Report Duplicate | Flag | PURGE
Cisco Systems Software Engineer / Developer - 9
0of 0 votes
AnswersWhat does the following program do ?
- Vezita in India
main ()
{
unsigned int num ;
int i ;
scanf("%u ", &num);
for(i=0;i<16;1++)
printf("%d",(num<<i & 1<<15) ? 1:0);
}
A. print all even bits from num
B. print all odd bits from num
C. prints binary equivalent of num| Report Duplicate | Flag | PURGE
Cisco Systems Software Engineer / Developer C
2 methods -
1st for replacing
2nd for counting the number of occurrence of substring
//to replace the string
//original = "Microsoft", substr = "ic" ,Replacement = "MSFT"
public static String StringReplace(String original, String substr, String Replacement)
{
String[] arr = original.split(substr);
StringBuilder output = new StringBuilder();
int i = 0;
for ( ; i < arr.length-1 ; i++)
output.append(arr[i]).append(Replacement);
output.append(arr[i]);
System.out.println(output);
if(original.substring(original.lastIndexOf(substr)).equalsIgnoreCase(substr))
output.append(Replacement);
System.out.println(""+output);
return output.toString();
}
//count the number of ocurrence of the replacement
public int NumOccurrence(String original, String substr)
{
int nOccurrence=0;
int n=0;
while(n <= original.length())
{
if ((original.indexOf(substr , n)) == -1)
break;
else
{
n= original.indexOf(substr,n);
nOccurrence++;
n++;
}
}
return nOccurrence;
}
}
IF EXTRA SPACE is ALLOWED
use hashSet in java .
1. create a new hashSet HS
2. for every element in the array, check if hashSet contains the element (using HS.contains(element)) .
if the method returns False , then add the element in the hashSet .
3. Traverse next element in arrray and repeat step 2.
Space Complexity: O(n)
Time Complexity: O(n)
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this solution does not consider the condition when color is unknown.
- Vezita June 29, 2014