floaterions
BAN USER
seems the best one. I have another solution, which is harder to understand, but takes up less space. But I myself prefer your approach.
- floaterions January 14, 2013Your answer seems correct except the best case analysis. The best case, i.e. the least number of points that put your team through, is 8 points.
Team A = 14
Team B = 12
Team C = 10
Team D = 8
Team E = 6
Team F = 4
Team G = 2
Team H = 0
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@chris: the interviewer explicitly states that the method could get called very often. So, sorting is not cheaper than pre-processing and constant lookup. To be more precise, assume that we will call this function m times a day.
- floaterions January 14, 20131) This algorithm: O(n*86400) + m* O(1)
2) Using sorting: O(m*n*logn)
Obviously, for even almost large values of n and m, the first algorithms works better