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public int getMaxSum(int [] arr,int k,int sum){
if(k==2||k==1||k==0)
return sum+arr[0]+Math.max(arr[1], arr[2]);
else{
return sum +arr[k] + Math.max(getMaxSum(arr, k-1,sum), getMaxSum(arr, k-2,sum));
//return sum;
}
1.Initialize an array temp[] of the size of the target sum.
2.Iterate over the array
3.If arr[i] = k then
i.if temp[k] == 0
ii. mark temp[k] = 1 and temp[target sum - k] = -1
iii. if temp[k] == -1 then pair found print k and target sum - k
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They will give three problems.First one easy probably on arrays next one on trees and the third a design problem.How many problems they give also depends on how fast you solve the problems.The interview will last for 1 hr.The interviewer will help you in all possible way so discuss the problems and your thought process.All the best.
- roykanti.blr June 09, 2015