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since first row will have 1 star 2nd row 3 star 3rd row 5 star so on.
- amit.99531 October 23, 2018so to make n row you should have total star equal to sum of first n odd numbers.
As you can see above first n odd number form Arithematic progression with difference of 2
sum of n numbers of an Arithematic progression =(n* (2*a+(n-1)*d))/2
where n = number of term
a(first term) = 1
d(difference) = 2
so sum = (n*(2*1+(n-1)*2)/2 = n*n = n^2
so you simply have to check number of star is perfect square or not.