Denis
BAN USERI am a Master's student at SFSU,San Francisco. Looking for a Job Starting from 2017 and a summer internship for 2016.
My Major is computer science.
Using C:
It sorts the user provided array first and then just alternately add the elements in the array.
#include <stdio.h>
void sort(int arr[],int left,int right)
{
int i= left, j= right;
int pivot = arr[((left+right)/2)];
int tmp=0;
/* partition */
while(i<=j)
{
while(arr[i]<pivot)
i++;
while(arr[j]>pivot)
j;
if(i<=j)
{
tmp = arr[i];
arr[i] = arr[j];
arr[j] = tmp;
i++;
j;
}
};
/* recursion */
if(left<j)
sort(arr,left,j);
if(i<right)
sort(arr,i,right);
}
int main()
{
int i;
int arr[7] = {1,2,3,4,5,6,7};int max=0,min=0;
int result[7];
int len = (sizeof(arr)/sizeof(arr[0]));
//printf("%d\n",arr[0]);
sort(arr,0,len1);
//printf("%d\n",arr[0]);
for(i=0;i<len;i++)
{
if(i%2==0)
{
result[i] = arr[(len1max)];
max++;
}
else
{
result[i] = arr[min];
min++;
}
printf("%d\n",result[i]);
}
return 0;
}

Denis
June 24, 2016 ++ is an increment operator. increment operator before the variable has the higher priority than any other operator involved with the variable. It is called preincrement operator. If increment operator is after the variable than it is called the post increment operator It has the lower priority.
In the given code you have preincrement operator's so when you apply plus operations first the value of the variable is increased then it is added to the another variable. like
z = (++y) + ++x + ++x; //here first the value of y increase than it is added to the value of x like the normal plus operation. Similarly for the other x varialbes.
But if it was like this:
z = ++y + x++ + ++x;
Here in case of first x it will add the value of x first to y and that value is added to the second x variable.But by the time control goes to the second x,the value of x is already increased by 1 in the post increment operator. So, the addition would be like this
z = 9 + 1 + 3
If we have the sample data as given above 
Find the unique variables in the data and we can make a table like this below
A B C D
5 5 0 0
0 8 8 0
0 0 9 9
10 0 0 10
0 11 0 11
12 0 12 0
Sum3 8 13 8
So finally we can take out the 3 and 13 Rs from A and C and add 8 and 8 into A and D
So, the total number of transactions = 4.
Also, we can verify the calculation by checking the Total of all the sum which should be zero.
Sum of A+B+C+D=0
3+813+8=0
{{
int x=0;
boolean negative = false;
String out="";
System.out.println("Please enter the input");
Scanner sc = new Scanner(System.in);
x = sc.nextInt();
if(x<0){
negative = true;
}
x = Math.abs(x);
while(x>0){
out = x%10+out;
x =x/10;
}
if(negative)
out = ""+out;
System.out.println(out);
}}
Open Chat in New Window
Does the i has to be less than j? Because A[i]A[j] can be negative if i is greater than j in this array. which is less than ij and fulfills the condition.
 Denis September 28, 2016