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using 0 to represent 4, 1 to represent 7.
say x is n digit iterate from 00..0(n digits) to 11..1(n digits),
and convert binary to lucky number and compare to x
if no number is larger than x, increase one digit add test again.
e.g. 43 is 2 digits, iterate from 00 to 11, as a result 01 (represents 47) > 43, the next lucky number is found.
- huxing.zhang April 20, 2014