sonyjames9
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0
of 0 vote
#--Count Dup Numbers in Array
a = [1,1,2,2,3,4,1]
b = []
l = a.length
for i in 0...l
chr = a[i]
if !(b.include? chr)
b << chr
end
end
puts "#{b}"
bl = b.length
for i in 0...bl
cnt = 0
for j in 0...l
if b[i]==a[j]
cnt = cnt +1
end
end
puts "#{b[i]} #{cnt}"
end
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0
of 0 vote
#--Count Dup values Ruby
a = String.new("aabccdd")
b = ""
l = a.length
for i in 0...l
chr = a[i]
if !(b.include? chr)
b << chr
end
end
puts b
bl = b.length
for i in 0...bl
cnt = 0
for j in 0...l
if b[i]==a[j]
cnt = cnt +1
end
end
puts "#{b[i]} #{cnt}"
end
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0
of 0 vote
a = [1,2,3,4,5,6,7,8,9,10,11]
b = Array.new
l = a.length
n = 5
start=0
endv=n
(0...l).step(n) do |i|
for j in (endv-1).downto(start)
b << a[j]
end
start= start + n
endv = endv + n
end
puts b
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- sonyjames9 July 07, 2016