iamkake
BAN USER
- Create a mapping between entry (string?) and int
- Go through the list and for each increment the int by 1 so at the end you have a count of everything
- Go through the mapping you made and for each if there is only 1, print it out, if there is more than 1 print it out the number in the mapping minus 1
public string[] filter(string[] everything)
{
if (everything == null || everything.length < 2) { return everything; }
HashMap<string,int> counts = new HashMap<string,int>();
for (int i = 0 ; i < everything.length; i++)
{
if (counts.containsKey(everything[i]))
{
counts.put(everything[i],counts.get(everything[i]) + 1);
}
else {
counts.put(everything[i], 1);
}
}
List<string> finalList = new ArrayList<string>();
for (Map.Entry<string, int> entry : map.entrySet()) {
int times = entry.getValue();
if (times == 1) {
finalList.add(entry.getKey());
}
else {
for (int i = 0; i < times - 1; i++)
{
finalList.add(entry.getKey());
}
}
}
string[] arrayFinal = new string[finalList.size()];
finalList.toArray(arrayFinal);
return arrayFinal;
}
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and the only column is a1 and a2??
- iamkake April 30, 2014