Adobe Interview Question for Software Engineer in Tests


Country: United States




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11
of 11 vote

delete from employee where rowid not in (select min(rowid) from employee group by firstName , lastName)

- entityvsentityv2 August 02, 2012 | Flag Reply
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0
of 0 votes

it will delete all duplicated instance..

- nikhilranjan234 August 14, 2012 | Flag
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0
of 0 votes

Query is fine.. Nikhil... Hw can it deletes all duplicates ??

- dildileepkumar October 06, 2012 | Flag
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0
of 0 votes

absolutely correct query cause for each insert there would be unique index generated no mattr insertion is repeated or not. In answer d query is deleting the duplicate indices using Not in.

- swapnil January 06, 2013 | Flag
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3
of 3 vote

delete from Emp where Emp.EmpId IN (select EmpId from Emp Emp2 where Emp.FirstName = Emp2.FirstName and Emp.LastName = Emp2.LastName and Emp2.EmpId <> Emp.EmpId)

- Elijah July 31, 2012 | Flag Reply
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0
of 0 votes

Won't this delete every instance of duplicated data?

Perhaps we should do Emp2.EmpId > Emp.EmpId, rather than <>.

- Anonymous August 01, 2012 | Flag
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0
of 0 votes

Yeh this will delete all duplicate values

- Hoper October 11, 2012 | Flag
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0
of 0 vote

ALTER IGNORE TABLE emp ADD UNIQUE INDEX(first,last)

- woggle August 20, 2012 | Flag Reply
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0
of 0 vote

delete from employee where employeeId in 
(
select top 2 employeeid from employee where 
employeename in (select employeeName from employee group by employeeName having count(*) > 1) order by employeeId desc)

- Niraj November 30, 2012 | Flag Reply
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0
of 0 vote

use CTE

- ayangyang June 02, 2013 | Flag Reply
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0
of 0 vote

You could use Rank() function to identify the duplicate row

Select Rank() over(Partition by firstname, lastname order by rowid) rank_n, RowId, FirstName, LastName from Employee

The above function will give you the ranking based on the firstname and lastname combination.

delete the records for the identified rowId's from above query where rank_n >1

- Raj July 09, 2013 | Flag Reply
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0
of 0 vote

with CTE as
(select *,row_number() over(partition by FirstName,LastName order by firstname) as RR
from ee1)
delete from CTE where RR>1

- Sushil September 02, 2013 | Flag Reply
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0
of 0 vote

del from emp
where id not in (sel min(id) from emp group by fname, lname having count(*)>=1)

- Shruti September 05, 2013 | Flag Reply
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0
of 0 vote

;with cte as
(
select *, row_number() over (partition by name order by name desc) as dup_name from name)
delete from cte where dup_name>1

- Ayushi June 15, 2014 | Flag Reply
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-1
of 1 vote

Select emp id, first name, last name, count (*) from EMP
Group by first name, last name
where count(*) > 1

this will return the duplicate records and Delete it using delete query....

- Gyanendra prasad Giri September 02, 2012 | Flag Reply
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0
of 0 votes

This query wont work - the group by clause wont let you have the emp id in the select clause, as you are aggregating on first and last names.

- Makarand May 30, 2013 | Flag
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Comment hidden because of low score. Click to expand.
Comment hidden because of low score. Click to expand.
Comment hidden because of low score. Click to expand.
1
of 1 vote

This code works fine for me. have used Common Table expressions .

WITH CTE_1
AS (
SELECT first_name, last_name, ROW_NUMBER() OVER (ORDER BY first_name,last_name) AS keep_ID ,
DENSE_RANK() OVER(ORDER BY first_name,last_name) AS RANK FROM persons_cup)
DELETE FROM CTE_1 WHERE keep_ID NOT IN
(SELECT MIN(keep_id) FROM CTE_1 B GROUP BY RANK)

- Nilesh.K.Molankar October 15, 2012 | Flag
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0
of 0 votes

This one works !!

- Vishal December 31, 2012 | Flag


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