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Yahoo Interview Question Software Engineer / Developers

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    There is a temple, whose premises have a garden and a pond. It has 4 idols, each of Ram, Shiv,
    Vishnu and Durga. The priest plucks x flowers from the garden and places them in the pond. The number of flowers
    doubles up, and he picks y flowers out of them and goes to offer it to Lord Ram. By the time he reaches
    to the pond, he finds the remaining flowers also have doubled up in the meantime, so he again picks up y
    from the pond and goes to Lord Shiv.This process is repeated till all the Gods have y flowers offered to them,
    such that in the end no flower is left in the pond. Find x and y.

    - gullu on September 12, 2010 Report Duplicate | Flag
    Yahoo Software Engineer / Developer Brain Teasers

More Questions from This Interview

Comment hidden because of low score. Click to expand.
1
of 1 vote

x = 15 and y = 16

- Anonymous on September 13, 2010 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

right 2(2(2(2x-y)-y)-y)=y
gives x=(15/16)y;
put y =16 to makes x least integer as 15;

- saumils1987 on September 13, 2010 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

x = 3 y = 4
1. put 3 flowers in pond => 6(3*2) flowers
2. pick 4 flowers to lord Ram, 2 flowers left in pond
3. flowers double => 4(2*2) more in pond
4. pick 4 more flowers lord Shiv
5. No flowers in pond

Generic:
step 1: x => 2x
step 2: 2x-y
step 3: 2x-y => 2(2x-y)
step 4: (4x-2y)-y
step 5: 4x-3y = 0

hence x = (3/4)y or y = (4/3)x

- Anonymous on August 23, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

@above:dude read d question again...flowers sud b offered 2 all the 4 gods...and that 2 equal number of flowers...
x/y=15/16..

- qwerty on September 02, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
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of 0 vote

@above:dude read d question again...flowers sud b offered 2 all the 4 gods...and that 2 equal number of flowers...
x/y=15/16..

- qwerty on September 02, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

The answer is x=15 and multiples;y=16 and multiples.(Since the question did not mention anything about the least number required).
Eg x=45 and y=48 also works.

- canmpuppala on January 30, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

why it can't be x=1, y=1

- bkhan on March 29, 2013 | Flag Reply


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