Interview Question


Country: India




Comment hidden because of low score. Click to expand.
0
of 0 vote

From inside Derived or outside the object? From the inside, you can call it like this: Base::func()
From the outside it's pretty tricky. I haven't found a proper method yet without messing with the vtable.
If the method wasn't virtual you could have called it like this:
obj->Base::func()

- Keenox September 25, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Ooops, If the method wasn't virtual, you could've simply called : obj->func() and it would've surely invoked Base's version. :-)

- JoyZombie September 27, 2015 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

#include <iostream>

class Base{
public:
void func(){
std::cout<<"base class func\n";
}
};

class Derived : public Base{
public:
void func(){
std::cout<<"derived class func\n";
}
};

int main(){

Base *obj = new Derived();
obj->Base::func();

return 0;
}

- kishoredbn September 26, 2015 | Flag Reply


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