Goldman Sachs Interview Question
Java DevelopersCountry: India
Interview Type: In-Person
pass by value. Even the references are copied to and then send. The copied value of reference refers to the same object, making confusion for the pass by reference. In the case of String, its an immutable object and there is a String pool for the string objects to any string argument would be taken as a new values and would not refer to the same string argument which is being passed.
All parameters in java are passed by value.
Primitives types values are copied: so any change to that parameter is not visible outside of the function.
For object is the reference that is copied when passed as a parameter: any change to the internal state of the object is visible outside, but a change to the reference itself is not visible outside. For example setting to null a parameter will not affect the external references.
I dont think you can say that. What about, if i create object of Integer class.
Integer i = new Integer(4);
and pass this to a function??
Integer is not the same as int Joey. It it is a wrapper class that holds an int as a value. If you can pass it into a function you can edit the content, just as you can with any other object. However, it is not the same as the primitive int, which is always passed by value.
Java is pass by value for primitives and pass by reference for object except wrapper and immutable objects. Array is an object so even you pass primitive array to function, it will change the value.
Java is only call by value irrespective of the arguement type passed. These examples are quoted from Core Java Volume 1.
//code
this doesn't change the primitive value of percent.Local variable x is destroyed as soon as the function ends.
That means you can only change the state(attributes) of an object but you cannot change the references stored in the variables a and b.
- mohdsalmanshaikh63 January 10, 2016Same is the case for ArrayList.
So JAVA ONLY USES CALL BY VALUE.