Ashok Rajpurohit
BAN USERGood at Algorithms, Puzzles and Quants.
I like Data Structures and C++.
in Free time I like to solve puzzles.
Ashok Kumar Rajpurohit
Email-ashok1113@hotmail.com
Contact no. – 9060626134
Bangalore
OBJECTIVE:
To obtain a position that will enable me to use my strong organizational skills, educational
background to grow professionally and personally.
EDUCATION:
University – MNIT from 2007 to 2011
Course- Bachelor in Technology in Electronics & Communication Engineering
CGPA- 6.53/10
School topper in Class X and Tehsil topper in Class XII.
Secured All India Rank 492 in AIEEE 2007.
WORK EXPERIENCE:
June 2011-Persent
Working as Software Engineer in Huawei Technologies, Bangalore.
Currently I am working on Malaysia MNTS project that mainly uses the SIP protocol.
Worked as a team member in SOAP Testing for Ecuador, Venezuela and Columbia VPN project.
Worked as a team member in SOAP Testing for Chile VPN Project.
Worked as a solo member for eConferenece Project for over 3 months in Congo Brazzaville.
Worked as a team member for eConference Project in Nanjing, China.
Worked as a team member for eSpace Project in Nanjing, China.
AREA OF INTEREST:
Problem Solving and Analytics
Programming
Application development
Algorithms
TECHNICAL SKILL SET :
Languages: C, C++.
Database Query Language: SQL, Oracle.
Software Packages: Ms Office.
EXTRA CURRICULAR ACTIVITIES:
Secured Second Rank in Robotics Competition organized by Electronica at state level.
Participated as a team member in Huawei internal UDP events and was 2nd runner up last month.
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Let's say the principle amount is m and interest rate is r% and is calculated annually. so after n years the amount will be m*(1+ r/100)^n.
- Ashok Rajpurohit January 30, 2014Here m=1 and r = 100 so the amount will be 1*(1+100/100)^n = 2^n.
given that 2^n = 15B. so n = ln(15B)
ln means log with base 2