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We know the best case can be when elements are increasing by +1. Check the first number of an array a[0] --> 4 and number to found is 10.
- Anonymous July 30, 2014diff = 10 -4 = 6.
Number​ should at most apperas at a[0+6] = a[6] --> 8 .
Repeat the process again untill you find the element. [10-8 = 2]
check for a[8] --> 10 (output the number).