Interview Question


Country: United States




Comment hidden because of low score. Click to expand.
4
of 4 vote

if the table is twocols with columns one and two the following query works:

$QUERY =
  "select sum(1), sum(if(one = two, 1, 0)), sum(if(one <> two, 1, 0)) " .
  " from twocols";

- kasterma January 04, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Consider a table persons2 with First Name and Last Name being the columns that are
being checked against each other and with an ID column for each row (it could be whatever unique key you would like)

--You can achieve the results you need using the Scalar Subquery below
select count(*) as totaRows, (select COUNT(*)
from persons2 b,
persons2 c
where c.id = b.id
and c.first_name = b.last_name
) as matchingCount,
(select COUNT(*)
from persons2 b,
persons2 c
where c.id = b.id
and c.first_name <> b.last_name
) as nonMatchingCount
from persons2 a

- Shri November 09, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

select count(*) as Total, 'Total Scan' as comments from < Table>
union
select count(*) as Total, 'Non Maching' as comments from < Table> where column1 <> column1
union
select count(*) as Total, 'Maching' as comments from < Table> where column1 = column1

- utk November 19, 2012 | Flag Reply


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