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Interview Question


Country: India



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1
of 1 vote

should be (Address of x - Address of y)/sizeof(int)., not necessarily be 1.

- alex March 27, 2012 | Flag Reply
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0
of 0 votes

Yes. It should be one if these variables are array elements

- chinni April 14, 2012 | Flag
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0
of 0 votes

Yes. It should be one if these variables are array elements

- chinni April 14, 2012 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 votes

Yes. It should be one if these variables are array elements

- chinni April 14, 2012 | Flag
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0
of 0 vote

If they are auto in the same function the answer should be 4. The stack grows from higher to lower, so p - q should give 4 bytes difference.i.e-, sizeof(int)

- Anonymous March 24, 2012 | Flag Reply
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0
of 0 votes

correction. The answer is one.

- Anonymous March 25, 2012 | Flag
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0
of 0 votes

out put c=1;
it is 1 why?

- Anonymous March 25, 2012 | Flag
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0
of 0 votes

it should be 4 the difference of two int pointers but its out put c=1 why?

- Anonymous March 25, 2012 | Flag
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0
of 0 votes

because these value stored in stack .so difference of address is 4 bytes (in 32 bit compiler) .after subtraction it will give 4 and devided it by 4 (4/4) it always give 1
so answer always 1.

- sachendra May 30, 2012 | Flag
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0
of 0 vote

Difference of two pointers gives an integer value. It gives (Address of x - Address of y)/sizeof(int).

- Rama Chandra Paital March 25, 2012 | Flag Reply
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0
of 0 votes

Difference of two pointers of some type "TYPE' gives the number of block of the type 'TYPE' b/w the two addresses. That's why the output will be 1.

- -- March 26, 2012 | Flag


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