CareerCup

it is always " -1 " as you shift any number of times because the sign bit is propagating so always there are all bits having value '1' .so ans is "-1"

1 = 0x0000000000000001 (4 byte integer)
-1 = 0xFFFFFFFFFFFFFFFF
-1 >> 2 = 0x3FFFFFFFFFFFFFFF

Now you are taking a byte out of it. Depending on endienness either this will be 3FFF(big) or FFFF (little)

it is always " -1 " as you shift any number of times because the sign bit is propagating so always there are all bits having value '1' .so ans is "-1"

it is always " -1 " as you shift any number of times because the sign bit is propagating so always there are all bits having value '1' .so ans is "-1"

any reason why printing it with printf("%c"), it is printing nothing..., is it that there is no chracter corresponding to all ones?

any reason why printing it with printf("%c"), it is printing nothing..., is it that there is no chracter corresponding to all ones?

it is always " -1 " as you shift right any number of times because the sign bit is propagating so always there are all bits having value '1' .so ans is "-1"

any reason why printing it with printf("%c"), it is printing nothing..., is it that there is no chracter corresponding to all ones?

i checked it by placing %c it is displaying some symbol.