CareerCup

i = 300;
=> i = 100101100 //in binary in word format => B B Hb 0001 0010 1100 where B = Byte and Hb = Half Byte

(A)=> in memory (assuming it is Little endian))

0x12345678 - 0010- 1100
0x12345679 - 0000- 0001
0x1234567a - 0000 - 0000
0x1234567b - 0000 - 0000

0x1234567c - Location of next intezer(location of ptr++ or ptr + 1 where ptr is an intezer pointer as ptr is of type int => on doing ++ptr it will increment by 4 byte(**size of int**))

when

(B)we do char *ptr = &i;
ptr will become of type char => on doing ++ptr it will increment by 1 byte(**size of char**)
so on doing ++ptr it will jump to location -> 0x12345679 (which has 0000- 0001)
now we are doing
*++ptr = 2
=> 0x12345679 will be overwritten by 2 => 0x12345679 will have 00**10** - 0000 instead of 000**1** - 0000

so the new memory content will look like this :


(C)0x12345678 - 0010 - 1100
0x12345679 - 0000- 0010
0x1234567a - 0000 - 0000
0x1234567b - 0000 - 0000

which is equivalent to => B B Hb 0010 00101100 where B = Byte and Hb = Half Byte
=> 556

What course..err.. company?

Sorry, actual answer will depend on whether the machine is big endian/little endian.

First, you will have to cast the pointer to int (&i) to a pointer to char (char*). As soon as you do it and increment it, you will be addressing the byte #1 (second byte) of the original int. So, the actual output will depend on the size of int and the endianness of the machine this code is compiled for.

it will print 300.
he is updating next memory
i=300 ->2000
*p=300
++p->2004
*p=2->2004
printf("%d",i)->2000 ====300

cannot assign integer to char pointer

Error

Gives error due invalid pointer assignment

o/p
556

answer is 556

556

I think it will give error, because first it is pointing to an allocated location, after that it is trying to point to next location and try to assign a value into it which is not allocated yet.