Interview Question


Country: United States




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Assuming the binary tree does not need to be a BST, simplest approach is to flatten out the tree first into an array, using depth-first search. The array will tell you how many elements exist, and which should be the root of a subtree; advantage of an array, is that you can pivot on any element(this is how quicksort does balancing internally!). The level input into the function merely tells you when to stop processing.

- Yev August 05, 2012 | Flag Reply
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Can u give an program implementation....

- pulkit.2810 August 06, 2012 | Flag
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I suppose that if you are just creating an arbitrary tree that is height balanced by and input you could recursively create the tree and stop when you hit a height equal to the provided level.

static BSTNode create_i(int height, int count)
{
    if (height == count)
	return null;

    BSTNode n = new BSTNode();
    n.Data = count++;
    n.Left = create_i(height, count);
    n.Right = create_i(height, count);
    return n;
}

- Code Monkey August 09, 2012 | Flag Reply
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Couldn't exactly understand the question.
What it actually takes input from the user, the value of a node and its level??
or just value of the node...

- Vivek August 16, 2012 | Flag Reply


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