CareerCup

c=((a)+(b)*(a*b-a))-((b-a*a)*(b)+(a));

Yeah this is the answer... it is 15

c=((a)+(b)*(a*b-a))-((b-a*a)*(b)+(a));
c =((2)+(3)*(2*3-2))-((3-2*2)*(3)+(2))
c=((2)+(3)*(4))-((-1)*(3)+(2))
c=((2)+12)-(-3+(2))
c=14-(-1)=15
SUM(X,Y) (X*Y) just means (x*y) and that is why the difference when applied by reverse, there are no brackets for x and y like ((x)*(y)) and MULT(X,Y) (X)+(Y) just adds x and y after calculating them. You should know that macro only replaces the code with the thing we tell it to replace it with. Its not a function which will calculate a value and return a solution which will takes its place. So simply replace your code with what is written in the macro exactly and the calculate

c=0 is wrong... I sorry actually i forgot to multiply before...
15 is correct..
i checked it

yeh, c=15 is correct answer

EXPLAIN with working

c=SUM(MULT(a,b),SUM(a,b-a))-SUM(SUM(b-a,a),MULT(b,a))
c=SUM((a)+(b), a*(b-a))-SUM((b-a)*a, (b)+(a))
c= SUM(5,2)-SUM(2,5)
c=10-10
c=0..


sorry it is 0 i think

yeh, answer c=15 is correct .
but can anyone explain the answer...

answer should be zero

Output: Kick the ass of the one who wrote those macros! Never ever write code that is doing like this (e.g. the name does not reflect what the function does).

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