CareerCup

It should print B A C.

confirmed it on an actual program!

ABC, when A is instantiated during declaration

BAC, when A is instantiated in C's constructor

class A
{
public A()
{
Console.Write("A");
}
}

class B
{
public B()
{
Console.Write("B");
}
}

class C : B
{
A a = new A();

// A a;

public C()
{
//a = new A();
Console.Write("C");
}
}

The ouput is B A C.
This how the code looks likes:
class A
{
A() { cout<<"A"<<endl;}
};
class B
{
B() {cout<<"B"<<endl;
A a1;
}
};
class C:public B
{
C()
{ cout<<"c"<<endl; }
};

int main()
{
C c1;
return 0;
}

Since problem is clearly saying C is having the instance of A class as private, so we are not considering it should be in constructor of C class:-

Output will be:- BAC
Code:-

public class A {
public A(){
System.out.println("A");
}
}

public class B {

public B(){
System.out.println("B");
}
}

public class C extends B{
private A a=new A();
public C(){
System.out.println("C");
}

public static void main(String arr[]){
C obj=new C();

}
}

Since problem is clearly saying C is having the instance of A class as private, so we are not considering it should be in constructor of C class:-

Output will be:- BAC
Code:-

public class A {
	public A(){
		System.out.println("A");
	}
}

public class B {

	public B(){
		System.out.println("B");
	}
}

public class C extends B{
	private A a=new A();
	public C(){
		System.out.println("C");
	}
	
	public static void main(String arr[]){
		C obj=new C();
		
	}
}

Just adding to the BAC consensus with my explanation.

If the interviewer asked why does it have to be this way?
My answer would be:
1) The parent class B must be constructed first to enable access to inherited elements during C's initialization => B;
2) The member variable *instance* A ("instance" means A is not an uninitialized reference*) of the class C must be called before the classes constructor or they can't be operated on in the constructer => A
3) The constructer C has the pre requisites required and can be invoked => C

* As some have pointed out *if* A was a pointer its constructer would not be called until A is explicitly created. But a pointer to A is not equivalent to an "instance of A" which the question references.

Why it should print A? C only has an instance of A,it is not saying that we use it anywhere...

It also depends on how you create A. If it's a simple C member (non dynamic), then you would probably initialize it in C's constructor. Also, C is a subclass of B. Then output would be B A C

It is a very simple question to determine whether candidate knows about RAII and inheritance in C++. I think it is not related to C#.

It should print ABC without any if.

It will print class B first, then C, then A. Because when C is instantiated, C will call super which print B, then print C and finally A