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infinite loop

for(test();test();test()) should be

for(test();test();test()) should be

01. It'll give compile time error given main "}" is not present.
02. If you add "}" at the end then:
(a) it'll give warning for "i" is declared but not used.
(b)for(test();test();test()) {/* do somethibng */}
translates into
for(3;3;3)
i.e. for(initial condition; FALSE; LoopExpression)
it'll print 2 once, as in C++ 0 is TRUE and >0 is FALSE.

it give compile time error because retutn type of test() is not mentioned.

It will print 2 infinite time.
But why do you declare i unnecessarily it will take space ( program optimization) mention return type of test() in definition.

#include<stdio.h>
test()//by default return type is int
{
return 3;
}
void main()
{
int i=2;
for(test();test();test())
{
printf("2");
}
getch();
return 0;
}

OUTPUT: Infinite Loop (if last ; is not there in for loop if it is there then compile time error)

Compile time error will come because return type of test is not mention and for loop consist of only two semicolon.

If you are not considering syntax errors then it will be a infinite loop other otherwise commpile time error.

this is compile time error. The error is for(test();test();test();). here if we get The output to this prgm. we change The for(test=i ,i= 2, i ++). I think this is The solution. It is not confirm.

no need to mention return type of test() because defaultly it takes integer

If compiled in C then infinite time 2 will be printed.

it give compile time error because retutn type of test() is not mentioned.

It will get compile time error because the return type of test() is not mentioned. If correct this, even then it will not compile due the for loop line. The expression in the for loop must be a boolean value. Moreover, a for loop statement cannot have more than 2 semicolons.