CareerCup

Yes you can convert one object into another object..
For example:
you have a class B constructor B(int b) and class A constructor A(int a1, int a2).
Now you want to convert A object into B object. So simply write a conversion operator in class A.
i.e. operator B(){const A a){
return B( a.a1);
}

I think the question is about explicit conversion operators.
Like that:

class A
{
  private:
  double d;

  public:
  A(double x):d(x){}
  operator double()
  {return d;}
}

In "main":

A a(2.0);
double dd;
dd=a;

Is this supposed to mimic the CAST? If so, however, every time when do conversion there must be a B object, instead of using B class type. I know we can't make operator() static, but is there some other way? Thanks!

type conversion operator is especially useful if some mathematics operations are to achieve.

class Foo; //wrapper of double
Foo a;
float b;
Foo c = a + b;