Barclays Capital Interview Question Solutions Architects
Country: United States
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Just create a graph in which each node corresponds single family member. Something like that:
class Node { Node mother; Node father; List<Node> children; }And construct a Map<String, Node> where key is a name and value is the node.
- Anonymous June 28, 2013If you need to find information about a particular person you can do it in O(1) time using map. To get information about his descendants use standard DFS.