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Interview Question for Software Engineer / Developers






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Output is : 1020

- Anonymous January 23, 2010 | Flag Reply
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@Anonymous..ur idea is correct. ## concatenates val1 and val2.
However in this case it would throw out an error stating that "val1val2" is not found

- Musheka January 24, 2010 | Flag Reply
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But why do we get this error ?

#define FUN(val1,val2) val1##val2
#define SQR(x,y) x##y

int main(int argc, char* argv[])
{
int val1=10;
int val2=20;
printf("%d\n",SQR(val1,val2));
// printf("%d\n",FUN(val1,val2));
return 0;
}

In this code the first printf works properly but the 2nd one fails. Is this because of some peculiarity in the ##operator ?

- abhimanipal January 31, 2010 | Flag
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none of the statements wrk

- kamal February 01, 2010 | Flag
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To get an output we need to define val1val2 .

- Anonymous January 25, 2010 | Flag Reply
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by definition do u mean defining their types in symbolic const stmt?

- seeker7 June 01, 2010 | Flag
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To get an output we need to define val1val2 .

- JD January 25, 2010 | Flag Reply
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This will not work because val1val2 is not a defined variable
If we add this line before it will work
FUN(val1,val2)= 100;

- dagnihot March 02, 2010 | Flag Reply
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O/P=1020
## concatenates the val1 and val2.

- Anonymous April 22, 2010 | Flag Reply
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#include<stdio.h>
#definr FUN(i) (i*i)
Int main()
{
Int x, y=3;
x = FUN(y+2);
Printf("%d\n", x);
return 0;
}

- Anonymous February 01, 2020 | Flag Reply


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