Google Interview Question for SDE1s


Country: United States




Comment hidden because of low score. Click to expand.
1
of 1 vote

public static boolean matcher(String pattern, String seq) {
        if (pattern == null && seq == null) return true;
        int lenPattern = pattern.length(), lenSeq = seq.length();
        int ptr1 = 0, ptr2 = 0;
        while (ptr1 < lenPattern && ptr2 < lenSeq) {
            char ch1 = pattern.charAt(ptr1);
            char ch2 = seq.charAt(ptr2);
            if (ch1 >= '1' && ch1 <= '9') {
                ptr1++;
                int rep = ch1-'0';
                ptr2 += rep;
            } else {
                if (ch1 == ch2) {
                    ptr1++; ptr2++;
                } else {
                    return false;
                }
            }
        }
        if (ptr1 != lenPattern || ptr2 != lenSeq) return false;
        return true;
    }

- Aim_Google January 09, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

boolean isValid(String pattern, String matcher)
{
   for(int i=0,j=0;i<pattern.length()&&;j<matcher.length();i++,j++)
{

if(Character.isDigit(pattern.charAt(i))
{
 int number=Integer.parseInt(pattern.charAt(i));
 if(number==1)
  continue;
 while(number>1)
     j++;
}
else if(patter.chartAt[i]!= matcher.charAt[i])
  return false;
else
  return true;
}

- Anonymous January 09, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public static boolean isValid(String pattern, String matcher)
{
   for(int i=0,j=0;i<pattern.length()&&j<matcher.length();i++,j++)
{

if(Character.isDigit(pattern.charAt(i)))
{
 int number=Integer.parseInt(pattern.charAt(i));
 if(number==1)
  continue;
 while(number>1)
     j++;
}
else if(patter.chartAt[i]!= matcher.charAt[i])
  return false;
else
  return true;
}

}

- hsg January 09, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public static boolean isValid(String pattern, String matcher)
{
   for(int i=0,j=0;i<pattern.length()&&j<matcher.length();i++,j++)
{

if(Character.isDigit(pattern.charAt(i)))
{
 int number=Integer.parseInt(pattern.charAt(i));
 if(number==1)
  continue;
 while(number>1)
     j++;
}
else if(patter.chartAt[i]!= matcher.charAt[i])
  return false;
else
  return true;
}
}

- hsgill88 January 09, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public boolean isMatch(@Nonnull final String matcher, @Nonnull final String text) {
        StringBuilder matchPattern = new StringBuilder();
        for (char c : matcher.toCharArray()) {
            if (c >= 48 && c <= 57) {
                matchPattern.append("[a-z]{").append(c).append("}");
            } else {
                matchPattern.append(c);
            }
        }
        Pattern pattern = Pattern.compile(matchPattern.toString(), Pattern.CASE_INSENSITIVE);
        return pattern.matcher(text).matches();
    }

- Scavi January 09, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public static bool IsPatternMatchingWithStringV2(string pattern, string str)
        {
            int i = 0 /* Pattern index*/,j=0 /*String index*/;

            for (i = 0; i < pattern.Length && j < str.Length; i++)
            {
                if (Char.IsDigit(pattern[i]))
                {
                    j += Convert.ToInt32(pattern[i].ToString());
                }
                else
                {
                    if (pattern[i] != str[j])
                    {
                        return false;
                    }

                    j++;
                }
            }

            return true;
        }

- Baz Jir Ipekyuz January 13, 2018 | Flag Reply


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