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What do you mean by setting a pixel exactly? Is it setting the value to 1? Since it is a monochrome monitor, all we have is Os and 1s. If the image is of size 800 by 600, then we need an array as big as 800 * 600 (800 rows and 600 cols). So, iterate through each element in the array and keep track of the cols and rows and set the bits accordingly..please correct me if I am wrong...

Given pixel(x, y) element in the 1D array is x*800+y.

To add Monochrome doesn't mean just one color. It is shades of a single color.

assumed the 1D array is a bit array which givs either present or absent of the pixel

long count = 0;
while(count < 480000/*=800x600*/)
{setpixel(count%800/*x*/, count/800/*y*/,/*color*/);count++;}

If the pixels are stored in row major, we need to set the array's index(say i) given x, y.
and assuming 1,1 is at top left corner and array index starts from 0

i = (y-1)*800 + (x - 1)

screen resolution is columns x rows

This is bit vector.

shouldn't it be (y-1)*600+x;

Assume the screen has 800 rows and 600 columns.Initialize the screen as a 1D array

int *ptr = (int *) malloc (800*600*sizeof(int));

Now if I want to set the pixel (400,300) = (i,j)

int i = 400;
int j = 300;

*((600*i)+ ptr + j) = 1;

Am I correct?

yes nick i think u are right..

address_index=base_adrees+(row)*600*sizeof(int)+col;
*address_index=1;

and also check if (row)>=0 and row<800 and col>=0 and col<600;