Interview Question


Country: China
Interview Type: Phone Interview




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of 0 vote

Read "Concrete mathematics". Also, read [ en.wikipedia.org/wiki/Josephus_problem ].
[ geeksforgeeks.org/josephus-problem-set-1-a-on-solution/ ]

- NoOne February 09, 2018 | Flag Reply
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0
of 0 vote

#include<iostream>
using namespace std;

int josephus(int n, int k)
{
  if (n == 1)
  {
    return 1;
  }
  else
  {
     // The position returned by josephus(n - 1, k) is adjusted because the recursive call 
     // josephus(n - 1, k) considers the original position (k%n + 1) as position 1
    return (josephus(n-1, k) + k-1) % n + 1;
  }
}

int main()
{
  int n;
  int k;
  cout << "Number of people in circle :";
  cin >> n;
  cout << "Number of people to skip :";
  cin >> k;
  cout << "Safe place to stand is :" << josephus(n, k) << endl;
  return 0;
}

- Vishal Rastogi April 19, 2018 | Flag Reply
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0
of 0 vote

#include<iostream>
using namespace std;

int josephus(int n, int k)
{
  if (n == 1)
  {
    return 1;
  }
  else
  {
     // The position returned by josephus(n - 1, k) is adjusted because the recursive call 
     // josephus(n - 1, k) considers the original position (k%n + 1) as position 1
    return (josephus(n-1, k) + k-1) % n + 1;
  }
}

int main()
{
  int n;
  int k;
  cout << "Number of people in circle :";
  cin >> n;
  cout << "Number of people to skip :";
  cin >> k;
  cout << "Safe place to stand is :" << josephus(n, k) << endl;
  return 0;

}

- Vishal Rastogi April 19, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

it prints the last man alive.
The problem is to calculate the last two men alive.

- Chaman October 19, 2018 | Flag


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