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Texas Instruments Interview Question






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3
of 3 vote

code 1 is going to b better as..
no of comparisions in 1 are = 100 + 100*10000=1000100
100 for each increment of i and (10000*100) for each i we have 10000 k comparisions

but in code 2 total no. of comparisions are 10000 + 10000*100=1010000 > 1000100

- ashish kumar dey August 21, 2011 | Flag Reply
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0
of 0 votes

First one will be better.. Suppose we want to generate a delay. Inner loop suppose introduces a delay of 1 sec.. We can directly manipulate the overall delay by specifying i may be 10 or 100 for 10 sec or 100 sec delay resp.

- Harjot Singh September 16, 2011 | Flag
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0
of 0 vote

it Depends on what goes in <lines of code> and what you are accessing inside this.
From cache point,'2' code structure seems to be better, as read ahead scheme would be better for this.

- hari_nc February 10, 2011 | Flag Reply
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0
of 0 votes

Can you explain me in more detail please.

- Tosha December 05, 2014 | Flag
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0
of 0 vote

The first one. as we are doing condition check of k<10000 for only 100 times.

- Dipankar February 14, 2011 | Flag Reply
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0
of 0 votes

...but we are also doing a condition check of i<100 for 10000 times

- George October 03, 2014 | Flag
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0
of 0 vote

Both will take same time I guess

- Pratik K April 07, 2011 | Flag Reply
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0
of 0 vote

i think the 1st one because it will be lesser number of times execution will take place..

- Dennis Richie November 04, 2014 | Flag Reply


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