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Microsoft Interview Question for Software Engineer / Developers


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Comment hidden because of low score. Click to expand.
0
of 0 vote

char *strcat(char *dest, const char *src)
{
    size_t i,j;
    for (i = 0; dest[i] != '\0'; i++)
        ;
    for (j = 0; src[j] != '\0'; j++)
        dest[i+j] = src[j];
    dest[i+j] = '\0';
    return dest;
}

- Anonymous May 11, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

we have to make sure new string won't overwrite source string

char* mystrcat(  char*t,char*s)
{
	char* tmp=t;
	int sizet=strlen(t);
	if(s==NULL) return NULL;
	if(t==NULL) return s;
	if(s-t<=sizet+strlen(s)+1) return NULL;
	while(*(t+sizet++)=*s++);
	return tmp;
}

- Charles December 31, 2013 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

Hi Anonymous,
First you have to allocate memory for the src string that would be concatenated to the destination string.

- Abhishek July 26, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

char *myStrcat(char *s, const char *t)
{
char *p = s;

if (s == NULL || t == NULL)
return s; /* we need not have to do anything */

while (*s)
s++;

while (*s++ = *t++)
;

return p;
}

- aditya.bokaro August 16, 2011 | Flag Reply
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0
of 0 vote

char * mystrcat(char* s1,char* s2)
{
while(*s1)
s1++;
while(*s2)
*s1++=*s2++;
return s1;
}
}
int main()
{
char*s1="rajnesh",*s2="kumar";

printf("%s",mystrcat(s1,s2));
}

- Rajnesh March 22, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

core dump

- sanjay October 17, 2014 | Flag


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