CareerCup

Undefined behavior ("Between the previous and next sequence point an object shall have its stored value modified at most once ...").
But even if that was not the case, the order in which the two sub-expressions, b++ and ++b, are evaluated is unspecified. Finally, when the post increment happens is unspecified as long as it is after the value of b++ has been determined and before the next sequence point.

16

I think it is NOT undefined. It must print 16.

@alex.. it is undefined... when you have two increment operators in a single statement... something called side- effect occurs and each and every compiler handles this side effect in their own way.....

yes it is undefined behaviour

its 16.value will pass through from right and will be only one increment.

thanks

It might be dependent on the compiler. I tried on ideone, it generates a warning, but still prints the output (16), and b has been updated to 5.

16

@rajeev...why do u try for microsoft ? its paying just 8.5...try in fb..45 lpa

It's undefined. If you feel otherwise, put on your asbestos suit and file a bug report against either GCC (16) or Clang (15).

i tried in C#
Console.Write(b++ * ++b);

it gave me 15,

it is assiging value first and then incrementing when i say b++,
where as it is incrememting value first and assigning value when i say ++b
so it becomes 3*5 = 15

A C++ project in Visual Studio 2010 gives the answer as 16.. :) and so it should be...
In C# and Java it has to be 15...