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follow the idea of "level order traversal with spcl node at the beginning of each level"
- DimKnight August 20, 2013We have "a#bc#" for, where '#' stands for the end of a level
a
a->left = b
a->right= c
We have "a#$c#" for, where '$' stands for missing a child
a
a->left = NULL
a->right= c
We have "a#&#" for where '& stands for missing both children'
a
a->left = NULL
a->right= NULL
Perform a BFS from the root to output the string.
Following the rule should be able to reconstruct the same tree.