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int a=2038074743;
int n=1;
int low,high;
low = (6*n)-1;
high = (6*n)+1;
if(a<=3) cout<<"Prime"<<endl;
else
{
while(low<=a)
{
if((a-low) == 0)
{
cout<<"Prime"<<endl;
break;
}
if(high<=a)
{
if((a-high) == 0)
{
cout<<"Prime"<<endl;
break;
}
}
n++;
low = (6*n)-1;
high = (6*n)+1;
}
}
if(low>a)
cout<<"Not Prime"<<endl;
What if you use 2 pointers and make one pointer ahead of another.
-if they are diff., then increment both pointers
-if they are the same, move pointer 2 (the one ahead) and find a value opposite to the pointer 1, then swap with pointer1++. Then put pointer1+=1 and bring back pointer 2 to pointer1++.
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XOR with 1's
- goku December 03, 2007