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The idea is that, looking at the number from the right-most digits, you break out one or two characters, then recursively post-fix these broken out characters to all permutations of the remainder of the string.
Example:
1123
Step 1 (post-fix: ''):
Look at right-most characters: 23.
This is less than 26, so we can have 11+w (Step 2a) or 112+c (Step 2b).
Step 2a (post-fix: 'w'):
Look at right-most characters: 11
This is less than 26, so we can have +kw or 1+aw
Step 2b (post-fix: 'c'):
Right-most characters: 12
Less than 26, so we can have 1+lc or 11+bc
... and so on
Here is the code in Objective-C.
- Mani March 15, 2016