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For the 2nd solution, you will want to check the number at every index, not only the even-index ones. Otherwise it will not work, as shown by the counter example given previously by the other person: 8 9 6 7 => 9 8 7 6
- nanmeng1983 October 04, 2014So you should do as such (0-index):
at even index i, swap A[i] and A[i+1] if A[i] < A[i+1]
at odd index j, swap A[j] and A[j+1] if A[j] > A[j+1]