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Amazon Interview Question for Software Engineer / Developers


Team: AWS
Country: United States
Interview Type: Phone Interview
More Questions from This Interview



Comment hidden because of low score. Click to expand.
1
of 1 vote

int main()
{
ifstream fin;
fin.open("a.in");
 int flag=0,w=0;
char ch;
    while(fin.get(ch)&&ch!=EOF)
    {
        cout<<ch;
        if(ch==' '||ch=='\t'||ch=='\n')
        flag=0;
        else if(flag==0)
        {flag=1;
        w++;
        }
    }
    cout<<w;

}

- aakash01 December 26, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

I think we can use the string tokenizer function with space (" ") as one parameter .Then we can put a counter after the strtok and we can know the number of words.

- psaikaushik December 24, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

corner case: handle one long word

- Anonymous December 25, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

One solution: read char by char, and count the "whitespaces". With this algo, amount of memory is not an issue.

- Anonymous December 25, 2011 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 votes

We just can't count spaces because there can be multiple whitespaces between words, and there can other delimiters between words like comma, period, semi-colon etc.
So, one solution can be have a Finite State machine with may be like 2 states (READING_WORD, IN_DELIMITER) and calculate the state transition from IN_DELIMITER -> READING_WORD which should give number of words.

- Chethan December 29, 2011 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 votes

Could you please eloborate the solution

- Srishti January 19, 2012 | Flag


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