Interview Question


Country: United States




Comment hidden because of low score. Click to expand.
3
of 3 vote

If P(n) is the number of processes created by a n-fork program, then we have that

P(n) = 2 * P(n-1).

(first fork creates two copies of the n-1 fork program)

P(1) = 2.

P(2) = 2 * P(1) = 4.

So P(3) = 3 * P(2) = 8

In general, P(n) = 2^n

- Anonymous February 23, 2013 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

Child Processes=2^n-1 // n= no. of times fork called..
Total 7 Child processes and 1 initial parent process...Hence total 8 processes.

- Ashish February 23, 2013 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 3 vote

when ever u encounter a fork it divide the current process in 2 part,one continue for the parent process and another branch as another child process.
In above example:-
the total no of process are 4

- go4gold February 23, 2013 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

You are wrong! Look above for the right answer!

- BitCoder February 28, 2013 | Flag


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