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Here is the code...

#include<stdio.h>
void combinations(int * result, int start, int prev);
const char * getcode(int digit);
void main()
{
	int result[7];
	for(int i = 0; i < 9; i++)
	{
		result[0] = i;
		combinations(result, 1 ,i);
	}
}
void combinations(int * result, int start, int prev)
{
	const char *code;
	int i,k=0;
	if(start == 7)
	{
		printf("\nCombination: ");
		for(i=0;i<7;i++)
			printf("%d ", result[i]);		
		return;
	}
	code = getcode(prev);
	k=0;
	while(code[k] != '\0')
	{
		result[start] = code[k++] - '0';
		combinations(result, start+1, result[start]);			
	}	
}
const char * getcode(int digit)
{
	char *code;
	switch(digit)
	{
		case 0: code = "46";
					break;
		case 1: code = "68";
					break;
		case 2: code = "79";
					break;
		case 3: code = "48";
					break;
		case 4: code = "39";
					break;
		case 5: code = "5";
					break;
		case 6: code = "17";
					break;
		case 7: code = "26";
					break;
		case 8: code = "13";
					break;
		case 9: code = "24";
					break;
	}
	return code;
}

Hi gauravk.18,
Seems that you've almost done, but missed the repetition clause in the given problem.

Linkan Chen: lkchen1128@gmail.com
If the code have problem, hope you can contact me.

vector<string> StringArray;

CreateTeleNum(vector<string> NumArray, char[] A, string StringNum,int i, int j, int level){
if(level==0){
for(int i=0;i<3,i++){
for(int j=0;j<4;j++){
if(A[i][j]!='*' && A[i][j]!='#'){
string ss;
ss.append(A[i][j];
CreateTeleNum(NumArray,A,ss, i, j,level+1);
}
}
else if(level<6){
string2=stringNum;
string2.append(A[i][j]);
CreateTeleNum(NumArray,A,StringNum,i,j,level+1);
if( (i+1<3)&&(j+2)){
if(A[i+1][j+2]!='*' && A[i+1][j+2]!='#'){
............................
}
}
.................
consider other 4 situation
}
else if(level==6){
NumArray.push_back(StringNum);
}