Amazon Interview Question for Software Engineers


Country: United States
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
0
of 0 vote

BFS solution:

import random
(n, m) = (10, 15)
(mx,s) = ([random.randint(0, 9) for _ in xrange(n*m)], random.randint(1, 50))
(v,l,r) = ([0]*m*n, [[[0], mx[0]]], [])
while l:
    nl = []
    for [p, ps] in l:
        if ps == s:
            r = p
            break
        if ps < s:
            pp = p[-1]
            for np in [pp + d for d in [-1, 1, -m, m]
                   if 0<=pp+d<n*m and abs((pp+d)%m - pp%m)<2 and v[pp+d] == 0]:
                v[np] = 1
                nl += [[p + [np], ps + mx[np]]]
    l = nl

def printm(mx):
    print ""
    for i in xrange(n):
        print '[' + ' '.join(map(str, mx[i*m:i*m+m])) + ']'
    
print "target =", s
printm(mx)
if r:
    printm([1 if i in r else 0 for i in xrange(n*m)])

Output:

target = 34

[9 1 1 6 9 1 4 8 5 3 2 5 9 4 4]
[7 1 6 6 3 6 9 3 3 7 0 9 3 0 1]
[9 2 6 7 3 7 0 7 8 1 6 7 0 7 5]
[0 3 3 3 4 2 9 4 8 5 4 5 0 9 0]
[4 3 1 4 4 4 5 0 6 9 5 7 8 7 5]
[4 7 1 4 6 5 4 0 1 9 0 1 8 6 0]
[6 8 5 9 7 8 3 6 7 5 5 1 0 4 4]
[1 6 2 9 8 2 5 9 7 4 9 9 7 5 5]
[9 1 9 9 0 9 5 6 4 9 4 4 9 9 9]
[4 1 5 3 1 5 9 0 2 4 1 2 8 4 3]

[1 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]

- adr June 10, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public class SumInMatrix {

    public static void main(String[] args) {
        int[][] input = {{9, 1, 1, 6, 9, 1, 4, 8, 5, 3, 2, 5, 9, 4, 4},
                        {7, 1, 6, 6, 3, 6, 9, 3, 3, 7, 0, 9, 3, 0, 1},
                        {9, 2, 6, 7, 3, 7, 0, 7, 8, 1, 6, 7, 0, 7, 5},
                        {0, 3, 3, 3, 4, 2, 9, 4, 8, 5, 4, 5, 0, 9, 0},
                        {4, 3, 1, 4, 4, 4, 5, 0, 6, 9, 5, 7, 8, 7, 5},
                        {4, 7, 1, 4, 6, 5, 4, 0, 1, 9, 0, 1, 8, 6, 0},
                        {6, 8, 5, 9, 7, 8, 3, 6, 7, 5, 5, 1, 0, 4, 4},
                        {1, 6, 2, 9, 8, 2, 5, 9, 7, 4, 9, 9, 7, 5, 5},
                        {9, 1, 9, 9, 0, 9, 5, 6, 4, 9, 4, 4, 9, 9, 9},
                        {4, 1, 5, 3, 1, 5, 9, 0, 2, 4, 1, 2, 8, 4, 3}};
        int sum = 34;
        int[][] output = new int[input.length][input[0].length];

        if(findPath(input, output, sum, 0,0)) PrintMatrix.printMatrix(output);
    }
    public static boolean findPath(int[][] matrix, int[][] output, int sum, int r, int c){
        System.out.println("Row: "+r+", Col: "+c+" Target: "+sum);
        output[r][c] = 1;
        if(sum-matrix[r][c]==0) {
            return true;
        }else if(sum-matrix[r][c]<0){
            output[r][c] = 0;
            return false;
        }

        if(r+1<matrix.length && output[r+1][c]!=1){
            boolean bottom = findPath(matrix, output, sum-matrix[r][c], r+1, c);
            if(bottom) return bottom;
        }
        if(r-1>-1 && output[r-1][c]!=1){
            boolean top = findPath(matrix, output, sum-matrix[r][c], r-1, c);
            if(top) return top;
        }
        if(c-1>-1 && output[1][c-1]!=1){
            boolean left = findPath(matrix, output, sum-matrix[r][c], r, c-1);
            if(left) return left;
        }
        if(c+1<matrix[0].length && output[r][c+1]!=1){
            boolean right = findPath(matrix, output, sum-matrix[r][c], r, c+1);
            if(right) return right;
        }

        output[r][c] = 0;
        return false;
    }
}

- huehuehuehue June 14, 2018 | Flag Reply


Add a Comment
Name:

Writing Code? Surround your code with {{{ and }}} to preserve whitespace.

Books

is a comprehensive book on getting a job at a top tech company, while focuses on dev interviews and does this for PMs.

Learn More

Videos

CareerCup's interview videos give you a real-life look at technical interviews. In these unscripted videos, watch how other candidates handle tough questions and how the interviewer thinks about their performance.

Learn More

Resume Review

Most engineers make critical mistakes on their resumes -- we can fix your resume with our custom resume review service. And, we use fellow engineers as our resume reviewers, so you can be sure that we "get" what you're saying.

Learn More

Mock Interviews

Our Mock Interviews will be conducted "in character" just like a real interview, and can focus on whatever topics you want. All our interviewers have worked for Microsoft, Google or Amazon, you know you'll get a true-to-life experience.

Learn More