CareerCup

int zc=0,l=0,max=0;
for(int i=0;i<nums.length;i++){

	if(nums[i]==0)
		zc++;
	while(zc>k){
		if(nums[l++]==0)
			zc--;
	}
	max=Math.max(max,i-l+1);
}

int zi=-1,l=-1,max=0;
for(int i=0;i<nums.length;i++){
	if(nums[i]==0) {
		if(!l<0)
			max=Math.max(i-l);
		l=zi+1;
		zi=i;
	}
}

int zc=0,l=0,max=0;
for(int i=0;i<nums.length;i++){
	if(nums[i]==0) {
		zc++;
	}
	while(zc>k){
		if(nums[l++]==0)
			zc--;
	}
	max=Math.max(max,i-l+1);
}

int zc=0,l=0,max=0;
for(int i=0;i<nums.length;i++){

	if(nums[i]==0)
		zc++;
	while(zc>k){
		if(nums[l++]==0)
			zc--;
	}
	max=Math.max(max,i-l+1);
}

iterate a given array while keeping track of max consecutive 1s so far and counting running consecutive 1s. Compare max so far and running num.

iterate the input array by counting the number of zeros.

#include <iostream>
#include <vector>
#include <algorithm>

std::pair<int, int> findMaxConsecutiveOnes(const std::vector<int>& nums, int k) {
    int start = 0, end = 0, zeroCount = 0, maxLen = 0, flipIndex = 0;
    int leftIndexForMaxLen = 0; // To remember where the maxLen sequence starts.

    for (; end < (int)nums.size(); ++end) {
        if (nums[end] == 0) {
            ++zeroCount;
        }

        // If we have more than k zeros in the window, shrink it from the left
        while (zeroCount > k) {
            if (nums[start] == 0) {
                --zeroCount;
            }
            ++start;
        }

        // Update maxLen and the starting index of maxLen
        if (end - start + 1 > maxLen) {
            maxLen = end - start + 1;
            leftIndexForMaxLen = start;
        }
    }

    // Find the index to flip. It's the leftmost 0 in the max sequence.
    for (int i = leftIndexForMaxLen; i < leftIndexForMaxLen + maxLen; ++i) {
        if (nums[i] == 0) {
            flipIndex = i;
            break; // We just need the first one to maximize the sequence.
        }
    }

    return {flipIndex, maxLen};
}

int main() {
    std::vector<int> nums = {1, 1, 1, 0, 1, 0, 0, 1};
    int k = 2;
    auto result = findMaxConsecutiveOnes(nums, k);
    std::cout << "Flip index for maximizing consecutive 1s: " << result.first
              << "\nAfter flipping, maximum consecutive 1s: " << result.second << std::endl;
    return 0;
}